Bud Abbott and Lou Costello Meet Frankenstein (1948)

<?php
  $url = "https://api.moviendb.com/v1/movie/3073";

  $ch = curl_init();
  curl_setopt($ch, CURLOPT_URL, $url);
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
  $response = curl_exec($ch);
  $httpCode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
  curl_close($ch);

  if ($httpCode === 200) {
    $data = json_decode($response, true);
    print_r($data);
} else {
    echo "Erro: " . $httpCode;
}
?>

<?php
$url = "https://api.moviendb.com/v1/movie/3073";

$response = file_get_contents($url);

if ($response !== false) {
    $data = json_decode($response, true);
    print_r($data);
} else {
    echo "Erro ao fazer a requisição";
}
?>

const url = 'https://api.moviendb.com/v1/movie/3073';

fetch(url, {
    method: 'GET',
    headers: {
        'Accept': 'application/json',
        'User-Agent': 'MovieDB-Client/1.0'
    }
})
.then(response => {
    if (!response.ok) {
        throw new Error(`HTTP error! status: ${response.status}`);
    }
    return response.json();
})
.then(data => {
    console.log(data);
    // Processar os dados aqui
})
.catch(error => {
    console.error('Erro:', error);
});

{
  "id": 93405,
  "name": "Round 6",
  "original_name": "오징어 게임",
  "overview": "Centenas de jogadores falidos aceitam um estranho convite...",
  "first_air_date": "2021-09-17",
  "vote_average": 8.0,
  "vote_count": 14250,
  "genres": [
    {
      "id": 18,
      "name": "Drama"
    },
    {
      "id": 9648,
      "name": "Mistério"
    }
  ],
  "seasons": [
    {
      "season_number": 1,
      "episode_count": 9,
      "air_date": "2021-09-17"
    }
  ],
  "created_by": [
    {
      "name": "Hwang Dong-hyuk"
    }
  ]
}