Scooby-Doo! and Krypto, Too! (2023)

When the Justice League goes missing and villains overrun Metropolis, theres only one team that can solve this mystery: Scooby-Doo and the gang! But wait, theres a new dog in town – Krypto – Supermans Superdog with Super Powers. Mystery Inc. will need all the help it can get when phantoms menace the Justice Leagues headquarters.

2023
Family
Fantasy
Animation
Mystery
Comedy
7.0
/8z9OuOrPwF9OOPnmA7wuH2AeJL.jpg Poster

Cast

Grey DeLisle
Grey DeLisle
Daphne Blake / Wonder Woman (voice)
Matthew Lillard
Matthew Lillard
Shaggy Rogers (voice)
Charles Halford
Charles Halford
Lex Luthor (voice)
Nolan North
Nolan North
Computer / Joker / Superman (voice)
Frank Welker
Frank Welker
Scooby-Doo / Fred Jones (voice)
Fred Tatasciore
Fred Tatasciore
Solomon Grundy / Perry White (voice)
P.J. Byrne
P.J. Byrne
J.B. (voice)
James Arnold Taylor
James Arnold Taylor
Jimmy Olsen / Rex Ruthor (voice)
Tara Strong
Tara Strong
Helen / Lois Lane / Harley Quinn (voice)
Kate Micucci
Kate Micucci
Velma Dinkley (voice)
Niccole Thurman
Niccole Thurman
Mayor Flemming (voice)

Images

Scooby-Doo! and Krypto, Too! Poster
Scooby-Doo! and Krypto, Too! Poster

Video

trailer Oficial

Scooby-Doo e Krypto - O Supercão - Trailer Dublado

trailer Oficial

Detailed Information

General Information

Original Title: Scooby-Doo! and Krypto, Too!

Creators: Hwang Dong-hyuk

Gender: Family, Fantasy, Animation, Mystery, Comedy,

Duration: 32-82 min

Classification: 16 anos

Production

Budget: $0.00

Revenue: $0.00

Awards and Recognitions

  • Emmy Award - Melhor Ator em Série Dramática (Lee Jung-jae)
  • Golden Globe - Melhor Ator Coadjuvante em Série (O Yeong-su)
  • Screen Actors Guild Award - Melhor Elenco em Série Dramática
  • Critics' Choice Television Award - Melhor Série Dramática

Interesting facts

  • A série se tornou a mais assistida da Netflix em seu lançamento.
  • O criador Hwang Dong-hyuk levou mais de 10 anos para desenvolver a série.
  • Os uniformes dos guardas foram inspirados em roupas de ginástica infantis.
  • O jogo "Batatinha Frita 1, 2, 3" é um jogo infantil coreano real.

API

Acesse os dados do filme/série através da nossa API REST. Use o endpoint abaixo para obter informações completas em formato JSON.

Endpoint da API

https://api.moviendb.com/v1/movie/1146348

Parâmetros: {type} = "movie" ou "tv" | {id} = ID do filme/série

PHP com cURL

<?php
  $url = "https://api.moviendb.com/v1/movie/1146348";

  $ch = curl_init();
  curl_setopt($ch, CURLOPT_URL, $url);
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
  $response = curl_exec($ch);
  $httpCode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
  curl_close($ch);

  if ($httpCode === 200) {
    $data = json_decode($response, true);
    print_r($data);
} else {
    echo "Erro: " . $httpCode;
}
?>

PHP com file_get_contents

<?php
$url = "https://api.moviendb.com/v1/movie/1146348";

$response = file_get_contents($url);

if ($response !== false) {
    $data = json_decode($response, true);
    print_r($data);
} else {
    echo "Erro ao fazer a requisição";
}
?>

JavaScript com Fetch

const url = 'https://api.moviendb.com/v1/movie/1146348';

fetch(url, {
    method: 'GET',
    headers: {
        'Accept': 'application/json',
        'User-Agent': 'MovieDB-Client/1.0'
    }
})
.then(response => {
    if (!response.ok) {
        throw new Error(`HTTP error! status: ${response.status}`);
    }
    return response.json();
})
.then(data => {
    console.log(data);
    // Processar os dados aqui
})
.catch(error => {
    console.error('Erro:', error);
});

Exemplo de Resposta JSON

{
  "id": 93405,
  "name": "Round 6",
  "original_name": "오징어 게임",
  "overview": "Centenas de jogadores falidos aceitam um estranho convite...",
  "first_air_date": "2021-09-17",
  "vote_average": 8.0,
  "vote_count": 14250,
  "genres": [
    {
      "id": 18,
      "name": "Drama"
    },
    {
      "id": 9648,
      "name": "Mistério"
    }
  ],
  "seasons": [
    {
      "season_number": 1,
      "episode_count": 9,
      "air_date": "2021-09-17"
    }
  ],
  "created_by": [
    {
      "name": "Hwang Dong-hyuk"
    }
  ]
}